Q:

2 Geometry Questions thank you guys :):)

Accepted Solution

A:
Answer:[tex]\large\boxed{Q5.\ x=45\sqrt2}\\\boxed{Q6.\ x=8\sqrt2,\ y=4\sqrt6}[/tex]Step-by-step explanation:Q5.x it's a diagonal of a square.The formula of a length of diagonal of a square:[tex]d=a\sqrt2[/tex]a - side of a squareWe have a = 45.Substitute:[tex]x=45\sqrt2[/tex]Q6.Look at the first picture.In a triangle 45° - 45° - 90°, all sides are in ratio 1 : 1 : √2.In a triangle 30° - 60° - 90°, all sidea are in ratio 1 : √3 : 2.Look at the second picture.from the triangle 45° - 45° - 90°[tex]a\sqrt2=8[/tex]        multiply both sides by √√2  (use √a · √a = a)[tex]2a=8\sqrt2[/tex]      divide both sides by 2[tex]a=4\sqrt2[/tex]from the triangle 30° - 60° - 90°[tex]x=2a\to x=2(4\sqrt2)=8\sqrt2[/tex][tex]y=a\sqrt3\to y=(4\sqrt2)(\sqrt3)=4\sqrt6[/tex]